X^2+9.5x=93

Solution for X^2+9.5x=93 equation:

X^2+9.5X=93

We move all terms to the left:

X^2+9.5X-(93)=0

a = 1; b = 9.5; c = -93;
Δ = b2-4ac
Δ = 9.52-4·1·(-93)
Δ = 462.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.5)-\sqrt{462.25}}{2*1}=\frac{-9.5-\sqrt{462.25}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.5)+\sqrt{462.25}}{2*1}=\frac{-9.5+\sqrt{462.25}}{2}
$